Question

Find the zeroes of the following quadratic polynomials : t²-17​

Answer 1

Step-by-step explanation:

$( {t}^{2} - 17)$

$it \: can \: be \: written \: as : \\ (t + \sqrt{17) \: } \: (t - \sqrt{17} )$

$we \: get \: : \\ t = - \sqrt{17} \: or \: t = \sqrt{17}$

So Zeroes are -√17 & √17

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Answer 2

Answer:

√17 & -√17

Step-by-step explanation:

t^2-17

=(t)^2 -(√17)^2

=(t+√17) (t-√17)

so,the value of t^2-17 is zero when t=√17 or, t=-√17