Math, asked by absrjt1234, 4 months ago

Find the zeroes of the following quadratic polynomials : t²-17​

Answers

Answered by Utkarsh00198
4

Step-by-step explanation:

( {t}^{2}  - 17)

it \: can \: be \: written \: as : \\ (t +  \sqrt{17) \: }  \: (t -  \sqrt{17} )

we \: get \: : \\ t =  -  \sqrt{17}  \: or \: t =  \sqrt{17}

So Zeroes are -√17 & √17

Please mark as Brainliest

Answered by bharatimaharana200
2

Answer:

√17 & -√17

Step-by-step explanation:

t^2-17

=(t)^2 -(√17)^2

=(t+√17) (t-√17)

so,the value of t^2-17 is zero when t=√17 or, t=-√17

Similar questions