Question

Find the zeroes of the following quadratic polynomials x2-x-6 and verify the relationship between the zeroes and the coefficients. Please answer these question it is very urgent and don't post the irrevant answer if you know then only give the answer.​

Answer 1

To Find :

• zeroes of Quadratic polynomial x² - x - 6

Solution :

Given Quadratic polynomial :

• x² - x - 6

›› x² - x - 6 = 0

›› x² - 3x + 2x - 6

›› x(x - 3) + 2(x - 3)

›› (x + 2 )(x - 3)

• x = -2 or x = 3

Verification :-

α + β = -2 + 3

α + β = 1 .....1)

αβ = -2 × 3

αβ = -6 .....2)

Let α and β are the zeroes of Quadratic polynomial.

x² - x - 6

• a = 1
• b = - 1
• c = -6

Sum of Zeroes = -b/a

α + β = -(-1)/1

Substituting value of α + β from 1)

1 = 1

Product of zeroes = c/a

αβ = -6/1

Substituting value of αβ from 2)

-6 = -6

LHS = RHS

Hence Relationship is Verified