Find the zeroes of the given polynomial- l (x) =x square + 2x+1 Fast plz
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l(x)=x^2+2x+1
x^2+x+x+1=0
x(x+1)+1(x+1)=0
(x+1)(x+1)=0
x=-1,-1
Hence roots of l(x) are -1,-1
x^2+x+x+1=0
x(x+1)+1(x+1)=0
(x+1)(x+1)=0
x=-1,-1
Hence roots of l(x) are -1,-1
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