Question

find the zeroes of the given polynomial px = x^2 minus 4x minus 5
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Answer 1

p(x) = x² - 4x - 5

p(x) = x² -5x + x - 5

p(x) = X(X - 5) + 1(X - 5)

(X+1)(x-5) = 0

if (X+1) is equal to zero then

X+1 = 0

X = $\fcolorbox{red}{yellow}{-1}$

if (x-5) is equal to zero then

X-5 = 0

X = $\fcolorbox{red}{green}{5}$

Hence $\mathfrak\red{-1}$ and $\mathfrak\purple{5}$ are the zeroes of polynomial......