Question

Find the zeroes of the given polynomials.
(1) p(x) = 3x
(ii) p(x) = x2 + 5x + 6
(iii) p(x)=(x+2)(x+3)
(iv)p(x) = x4 - 16
2
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Answer 1

Answer:

zero of p(x)= 3x is -3

zero of X2+5x+6 is -6/7

zero of (x+2)(x+3) is -6/2 or -3

zero of x4-16 is 4

Step-by-step explanation:

first take all expressions equal to 0

next take the numbers to +/- to zero and solve

Answer 2

Your answer is in attachment hope it helps you dear