Math, asked by prakash1188, 11 months ago

Find the zeroes of the given polynomials.
(i) p(x) = 3x
(ii) p(x) = x2 + 5x + 6
(iii) p(x)=(x+2)(x+3) (iv) p(x) = x4_16​

Answers

Answered by isafsafiya
2

Answer:

p(x)=3x

p(0)=3x0

=0

p(x)=x2 +5x +6

p(0)=0 x2+5x0 +6

=6

p(x)=(x +2)(x +3)

p(0)=(0+2)(0+3)

=2 x3

=6

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