Find the zeroes of the given polynomials.
(i) p(x) = 3x
(ii) p(x) = x2 + 5x + 6
(iii) p(x)=(x+2)(x+3) (iv) p(x) = x4_16
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Answer:
p(x)=3x
p(0)=3x0
=0
p(x)=x2 +5x +6
p(0)=0 x2+5x0 +6
=6
p(x)=(x +2)(x +3)
p(0)=(0+2)(0+3)
=2 x3
=6
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