Question

Find the zeroes of the given polynomials.
(i) p(x) = 3x
(ü) p(x) = x2 + 5x + 6
(iii) p(x) = (x+2)(x+3)
(iv) p(x) = x4 - 16​

Answer 1

Answer:

answer

to find zero of a polynomial p(x), equate p(x) to zero, and solve for x.

1. 3x = 0

=> x = 0 is the zero of p(x) = 3x

2. x^2 + 5x + 6 = 0

=> x^2 + 3x + 2x + 6 = 0

=> x(x + 3) +2(x + 3) = 0

=> (x + 2)(x + 3) = 0

=> x+2 = 0 and x+3 = 0

=> x = -2 and x = -3 are the zeros

3. (x+2)(x+3) = 0

=> x+2 = 0 and x+3 = 0

=> x = -2 and x = -3 are the zeros

4. x^4 - 16 = 0

=> x^4 = 16

=> x^4 = 2^4

=> x = 2 and x= -2 are the zeros

Answer 2

Answer:

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