Question

find the zeroes of the given polynomials
(ii) p(x) = x2 + 5x + 6
(iv) p(x) = x4 - 16​

Answer 1

Answer:

The zeroes of the polynomial

p(x) = x2 + 5x + 6

= x2 + 3x+ 2x + 6

=. x ( x + 3) + 2 ( x + 3 )

=. ( x+3) ( x+ 2 )

=. x = -3, -2

sum of zeroes = -b/a

-3 -2. =. -5

-5. = -5

verified

product of zeroes are = c/a

-3× -2. =. 6

6= 6

verified

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Answer 2

ii) p(x) =x^2 +5x+6

=x^2+3x+2x+6

=x(x+3)+2(x+3)

=(x+3)(x+2)

Hence zeroes =(-3),(-2)

iv)p(x)=x^4-16

0=x^4-16

16=x^4

(2)^4=x^4

2=x

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