Question

find the zeroes of the given polynomials p(x)=x2+5x+6​

Answer 1

Hey

x^2 + 5x + 6 = 0

x^2 + 3x + 2x + 6 = 0

x(x+3)+2(x+3) = 0

(x+2)(x+3) = 0

x + 2 = 0

x = -2

x + 3 = 0

x = -3

Answer 2

Answer:

-2 and -3

Step-by-step explanation:

p(x) = x^2 + 5x + 6

By Middle term splitting we get,

x^2 + 3x + 2x + 6 = 0

x(x + 3) + 2(x + 3)

(x + 3) (x + 2)

(x + 3)

x = - 3

(x + 2)

x = - 2

★ Verification

⇒ p(-3) = (-3)^2 + 5(-3) + 6

p(-3) = 9 - 15 + 6

0

⇒p(-2) = (-2)^2 + 5(-2) + 6

p(-2) = 4 - 10 + 6

0

★ Therefore the zeroes of polynomial p(×) = x^2+ 5x + 6 are -2 and -3.