Question

find the zeroes of the given problem p(x)=(x+2)(x+3)​

Answer 1

p(x) = (x+2)(x+3)

p(x) = x^2 + 5x + 6

p(x) = x^2 + 2x + 3x + 6

p(x) = x ( x + 2 ) + 3 ( x + 2 )

p(x) = (x + 3)(x + 2)

Answer:

The zeroes are -3 and -2.

Answer 2

Answer:

p(x)=(x+2)(x+3)

p(0)=(0+2)(0+3)

p(0)=(0)(0)

p(0)=0