Question

find the zeroes of the given quadratic polynomial x²-4x-5 by splitting of middle term​

Answer 1

Answer:

$x {}^{2} - 4x - 5 \\ x {}^{2} + x - 5x - 5 \\ x(x + 1) - 5(x + 1) \\ (x - 5)(x + 1) = 0 \\ x = 5 \: , - 1$

Answer 2

Answer:

${x}^{2} - 4x - 5 = 0\\ {x}^{2} - 5x + 1x - 5 = 0 \\ x(x - 5) \: 1(x - 5) \\ (x + 1)(x - 5) \\ x = - 1 \\ x = 5$

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