Math, asked by manoj12313, 7 months ago

Find the zeroes of the
of the gives polynomial
P(x)= x²-7X+6​

Answers

Answered by rishitsjoshi
0

Answer:

1 & 6. Plz, mark me brainliest.

Step-by-step explanation:

P(x)=x²-7x+6

x²-x-6x+6=0

x(x-1)-6(x-1)=0

(x-1) (x-6) = 0

x=1 and x=6

ao the zeros are 1 & 6

Answered by jaiswalabhay128
1

Answer:

x=1,6

Step-by-step explanation:

p (x)=x^2-7x+6

x^2-x-6x+6=0

x (x-1)-6 (x-1)=0

(x-1)(x-6)=0

(x-1)=0 or (x-6)=0

x=1 or x=6

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