Math, asked by wowgvurav, 3 months ago

find the zeroes of the p(x)=(x-3)(x+2)​

Answers

Answered by umitbarman1111
4

Answer:

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Answered by singhdipanshu2707200
1

Answer:

1)p

p(x) =  {x}^{2}  - 1x - 6 \\  \:  = (x - 3) = 0    \\ x = 3 \\ (x + 2) = 0 \\ x =  - 2 \\ so \: zero \: is \: 3 \: \: or  - 2

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