Find the zeroes of the p(x) = x3+4x2_9x_36 if two of its zeroes are equal in magnitude but opposite in sign.
Answers
Answered by
0
Hey Friend ☺
x^3 + 4x^2 - 9x - 36 = 0
》x^2 ( x + 4 ) - 9 ( x + 4 ) = 0
》( x + 4 )( x^2 - 9 ) = 0
》( x + 4 ) [ ( x )^2 - ( 3 )^2 ] = 0
》( x + 4 )( x - 3 )( x + 3 ) = 0
So the zeroes of the polynomial are - 4 , 3 & -3
Hope it helps you ..!!
✌
x^3 + 4x^2 - 9x - 36 = 0
》x^2 ( x + 4 ) - 9 ( x + 4 ) = 0
》( x + 4 )( x^2 - 9 ) = 0
》( x + 4 ) [ ( x )^2 - ( 3 )^2 ] = 0
》( x + 4 )( x - 3 )( x + 3 ) = 0
So the zeroes of the polynomial are - 4 , 3 & -3
Hope it helps you ..!!
✌
Similar questions