find the zeroes of the polnomials and verify the relationship between the zeroes and the coefficients x2 -2x-8
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x^2-2x-8
x^2-4x+2x-8
x(x-4)+2(x-4)
(x+2)(x-4)
x=-2,4
sum of zeroes= -b/a =2
product of zeroes=c/a =-8
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Answer:x2 – 2x – 8
= (x - 4) (x + 2)
The value of x2 – 2x – 8 is zero when x - 4 = 0 or x + 2 = 0, i.e., when x = 4 or x = -2
Therefore, the zeroes of x2 – 2x – 8 are 4 and -2.
Sum of zeroes = 4 + (-2) = 2 = -(-2)/1 = -(Coefficient of x)/Coefficient of x2
Product of zeroes = 4 × (-2) = -8 = -8/1 = Constant term/Coefficient of x2
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