find the zeroes of the polunomial fx=3x2-3x2-11x-3 when it is given that product of its zeroes -1
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1
there is some mistake in question i think so plz check it.
Gboat:
thanks
Answered by
3
some mistake your question
if 3x²-3x²-11x-3 replace to
3x²-11x-3
here,
f(x)=3x²-11x-3
then.
the product of the zeroes=-1
and the sum of the zeroes=11/3
then find the zeroes
D=b²-4ac
121+36
157
then one zero is 11-√157÷12
and other is. 11+√157÷12
so best of luck
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