Question

find the zeroes of the poly f(x)=
$x {}^{2} + \sqrt{2x} - 4$
​

Answer 1

Answer:

the zeroes are √2  and  -2√2

Step-by-step explanation:

given x² + √2x - 4

x = [ -√2 ± √(√2² - 4 (1)(-4) ) ] / 2*1

  = [ -√2 ± √(2+16 ) ] / 2

  = [ -√2 ± √18 ] / 2

  = [ -√2 ± √(9*2) ] / 2

  = [ -√2 ± 3√2 ] / 2

  = √2 (-1 ± 3) / 2

  =  (-1 ± 3) / √2

so, x =  (-1 + 3) / √2  or  (-1 - 3) / √2

=> x =  (2) / √2  or  (-4) / √2

=> x =  √2  or  -2√2

ie, the zeroes are √2  and  -2√2