Question

find the zeroes of the polynnomial p(x) = 3x^2+ 2x + 1

Answer 1

Answer:

(x+1)(3x-1)

x+1=0

x=-1

3x-1=0

x=1/3

Step-by-step explanation:

3x^2+2x+1

3x^2+(3-1)x+1

3x^2+3x-1x+1

3x(x+1)-1(x+1)

(x+1)(3x-1)

x+1=0

x=-1

3x-1=0

x=1/3