Question

find the zeroes of the polynomial 10x² - x - 3​

Answer 1

Answer:

hey here is your answer

Step-by-step explanation:

#10x²-x-3

#10x²-5x+6x-3

#5x (2x-1) + 3 (2x-1)

#(5x+3) (2x-1)

so,

5x+3=0. 2x-1=0

5x=-3. 2x=1

X=-3/5. X=1/2

Therefore,

zeroes of 10x²-x-3 are,

-3/5 and 1/2

hope it will help you...

Answer 2

☯GIVEN :

• $\bf {10x^2 - x - 3}$.

☯TO FIND :

• The zeros of the quadratic polynomial.

➲SOLUTION :

$\implies \sf{10x^2 - x - 3= 0}$

• By middle term splitting :

$\implies \sf{10x^2 +5x -6x - 3 = 0}$

$\implies \sf{5x \big(2x + 1 \big)-3 \big(2x+1\big) = 0}$

$\implies \sf{\big(2x +1 \big) \big(5x -3 \big) = 0}$

$\implies \sf{\big(2x + 1 \big) = 0 \: , \: \big(5x-3 \big) = 0}$

$\implies\sf{2x = 0 - 1 \: , \: 5x = 0 +3}$

$\implies\sf{2x = - 1 \: , \: 5x = 3}$

$\implies{\underline {\boxed{\purple{\bf{x = \dfrac{ - 1}{2} \: , \: x = \dfrac{3}{5}}}}}}$

$\huge{ \pink{ \therefore}}$ The zeros of the quadratic equation are $\bf{\dfrac{ - 1}{2}}$ and $\bf{\dfrac{3}{5}}$ .