find the zeroes of the polynomial 15+p(7-2p) and verify the relation between zeroes and coefficients
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Let p(x)= 15+p(7-2p)= 15+7p -2p^2 = -2p^2 +7p +15 .
For the zeros of the given polynomial ,
-2p^2 +7p +15=0
-2p^2 +10p -3p +15=0
-2p(p-5)-3(p-5)=0
(-2p-3)(p-5)=0
-1(2p+3) (p-5)=0
(2p +3 ) (p-5)=0
→2p+3 = 0 or , p-5 =0
Thus , p=-3/2 or , 5 are the zeros of the given polynomial
p(x).
Verification ,
Sum of zeros = (-3/2+5)=( -3+10)/2= 7/2 = -(7/-2)= -(coefficient of p)/coefficient of p^2 .
Product of zeros =-(3/2×5)=-15/2= (15/-2)=( constant term )/(coefficient of p^2)
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