Question

find the zeroes of the polynomial 15x2 - x - 6

Answer 1

$\underline{\large\bf{\mathfrak{Hello!}}}$

$= > 15 {x}^{2} - x - 6 = 0 \\ \\ = > 15 {x}^{2} - 10x + 9x - 6 = 0 \\ \\ = > 5x(3x - 2) + 3(3x - 2) = 0\\ \\ = > (3x - 2)(5x + 3) = 0 \\ \\ = > x = \frac{2}{3} \: or \: - \frac{3}{5}$

$\boxed{Therefore, \: zeros \: of \: polynomial \: are \: x = \frac{2}{3} \: or \: - \frac{3}{5}}$

$\bf{\mathfrak{Hope \: this \: helps...:)}}$

Answer 2

15x^2 - x - 6 = 0

15x^2 - 10x + 9x - 6 = 0. ( Splitting the middle term method )

5x ( 3x - 2 ) + 3 ( 3x - 2 ) = 0

( 3x - 2 ) ( 5x + 3 ) = 0

3x - 2 = 0

× = 2 / 3

5x + 3 = 0

× = -3 / 5

Hence 'x' equals 2 / 3 or -3 / 5