Question

Find the zeroes of the polynomial 16xsquare-25 and verify the relationship between the zeroes and the coefficients

Answer 1

16 x^2 can be written in the form of 16x^2+ 0x -25
by splitting the middle term =16x^2 + 20x-20x -25
= 4x(4x +5) - 5 (4x + 5)
= (4x+5) (4x-5)
so 4x+5 = 0 or 4x-5 =0
therefore x= -5/4 or x=5/4
now relationship of :
sum of zeroes = -b/a
=> 0 = 0
product of zeroes = c/a
=> -25/16 = -25/16
hence verified