Question

Find the zeroes of the polynomial
×^2-2×-3​

Answer 1

Answer:

${x}^{2} - 2x - 3 \\ \\ = {x}^{2} - 3x + x - 3 \\ \\ = x(x - 3) + 1(x - 3) \\ \\ = (x - 3)(x + 1)$

Answer 2

Step-by-step explanation:

${x}^{2} - 2x - 3 = 0$

${x}^{2} - 3x + x - 3 = 0$

$x(x - 3) + 1(x - 3) = 0$

$(x + 1)(x - 3) = 0$

$zeroes \: of \: the \: polynomial \: are \: - 1 \: \: and \: \: 3$