Question

Find the zeroes of the polynomial

2x^2- 2x -8.
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Answer 1

Step-by-step explanation:

let p(x)=2x²-2x-8

2x²-2x-8

=2x²-(8-2)x-8

=2x²-8x+2x-8

=2x(x-4)+2(x-4)

=(x-4)(2x+2)

p(x)=0

(x-4)(2x+2)=0

if x-4=0

x=4

if 2x+2=0

x=-2/2

x=-1

ZEROES=-1,4

HOPE THIS HELPS YOU