Question

find the zeroes of the polynomial 2x^2-5

Answer 1

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Hope it will help u

Answer 2

P(x)=2x^2-5=0
=>2x^2=5
=>x^2=5/2
=>x=
$\frac{ + }{ - } \ \sqrt{ \frac{5}{2} }$
(one root is with the positive sign and one with the negative)
Hope this helps