Question

Find the zeroes of the polynomial 2x^2-9.​

Answer 1

Answer:

the zeroes are

3divided by root2

-3divided by root2

Step-by-step explanation:

2x^2-9=(root2x-3) (root2x+3)

x=3divided by root2

x=-3divided by root 2

Answer 2

2x⁹−9

zeros of the polynomial

2x²−9=0

x²= 9/2

x=±3/√2