Find the zeroes of the polynomial 2x2- 7x+ 3 and hence find the sum and product of its zeroes.
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2x2 - 7x + 3
2x2 - (6+1)x + 3
2x2 - 6x - 1x + 3
2x ( x - 3) - 2 ( x - 3)
(2x - 1)(x-3)
x = 1/2
x = 3
sum of zeroes = -b/a
1/2 + 3 = -(-7)/2
1+6/2=7/2
7/2= 7/2
product of zeroes = c/a
1/2 × 3 = 3/2
3/2 = 3/2
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2x2 - (6+1)x + 3
2x2 - 6x - 1x + 3
2x ( x - 3) - 2 ( x - 3)
(2x - 1)(x-3)
x = 1/2
x = 3
sum of zeroes = -b/a
1/2 + 3 = -(-7)/2
1+6/2=7/2
7/2= 7/2
product of zeroes = c/a
1/2 × 3 = 3/2
3/2 = 3/2
please mark me as brainliest
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