Question

find the zeroes of the polynomial 2x3+3x2-11x-6.​

Answer 1

Step-by-step explanation:

p (x) = 2x3 + 3x2 - 11x - 6.

One zero is -3. So, (x + 3) is a factor of p (x).

Quotient = 2x2 - 3x - 2 = (2x + 1) (x - 2)

Thus, the other zeroes of p(x) are 2 and .

Hence, all zeroes of p (x) is -3, 2 and .

Answer 2

Answer:

Step-by-step explanation:

Step-by-step explanation:

p (x) = 2x3 + 3x2 - 11x - 6. One zero is -3. So, (x + 3) is a factor of p (x). Thus, the other zeroes of p(x) are 2 and