Find the zeroes of the polynomial 2x4+7x3-19x2-14x+30 ,if two of its zeroes are root2 and.Minus root 2
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Let p(x) = 2x^4 +7x^3 - 19x^2 -14x +30
Given zeroes = √2 nd -√2
Sum of zeroes (s) = √2 + (-√2)
√2-√2
0
Product of zeroes(p) = (√2)(-√2)
-2
W.K.T,... k(x^2 -sx +p)
therefore, x^2 -0x + (-2)
... x^2 -2
Since( x^2 -2 ) is formed from the zeroes of p(x), .. it must be the factor of p(x)
By dividing from p(x) ...we get
2x^2 + 7x -15
2x^2 +10x -3x -15
2x(x+5) -3(x+5)
(2x-3)(x+5)
x= 3/2 ,..x= -5
Hence , zeroes of p(x) are √2,-√2, 3/2, -5
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