Find the zeroes of the polynomial 2xsquare +7x-4
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Hey
Here is your answer,
2x^2 + 7x - 4 =0
2x^2 - x + 8x -4 =0
2x (x -1) +8(x -1)=0
(X-1)(2x+8)=0
X-1=0
X=1
2x+8=0
X=-8/2=-4
Hope it helps you!
Here is your answer,
2x^2 + 7x - 4 =0
2x^2 - x + 8x -4 =0
2x (x -1) +8(x -1)=0
(X-1)(2x+8)=0
X-1=0
X=1
2x+8=0
X=-8/2=-4
Hope it helps you!
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