Question

Find the zeroes of the polynomial 2y^3+y^2-2y-1​

Answer 1

Answer:

$y=1$ or $y=-1$ or $y=-\dfrac{1}{2}$.

Step-by-step explanation:

By splitting the terms,

$2y^3+y^2-2y-1$

$y^2(2y+1)-(2y+1)$

Pulling out common factors,

$(y^2-1)(2y+1)$

$(y+1)(y-1)(2y+1)$

The zeros are at $y+1=0$ or $y-1=0$ or $2y+1=0$.

The three zeros are $y=1$ or $y=-1$ or $y=-\dfrac{1}{2}$.