Question

Find the zeroes of the polynomial 3x^2 + 10x + 8?

Answer 1

3x^2 + 10x + 8

=> 3x^2 + 6x + 4x + 8

=> 3x ( x + 2) + 4(x +2)

=> ( x + 2)(3x + 4)

So,

Zeroes are (-2) and ( - 4/3)

Answer 2

↑ Here is your answer ↓
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$3x^2 + 10x + 8 = 0$

$3x^2 + 6x + 4x + 8 = 0$

$3x(x+2) + 4(x+2) = 0$

$(3x+4)(x+2) = 0$

Hence,

$x = -4/3, x = -2$