Question

find the zeroes of the polynomial √3x^2-11x+6√3

Answer 1

Heya user☺☺

3^1/2x^2 - 11x +6 × 3^1/2 = 0

3^1/2x^2 - 9x -2x + 6×3^1/2 = 0

3^1/2x(x - 3 × 3^1/2) - 2(x - 3×3^1/2) = 0

(x - 3×3^1/2)(3^1/2x - 2) = 0

x = 3×3^1/2
x = 2/3^1/2

Hope this will help☺☺☺

Answer 2

Sol : √3 x² - 11 x + 6√3

We have to split the middle term in such a way that its sum is equal to -11x and its product should be equal to first term and second term.

 = √3 x² - 9 x - 2 x + 6√3

 = √3 x ( x - 3√3 ) - 2 ( x - 3√3 )

  ( x - 3√3 ) ( √3 x - 2 )= 0

  ( x - 3√3 ) = 0 / ( √3 x - 2 ) or ( √3 x - 2 ) = 0 / ( x - 3√3 )

  x - 3√3 = 0                          or ( √3 x - 2 ) = 0

  x = 3√3.                             or  √3 x = 2
 
                                                      x = 2 / √3.


So, zeroes of polynomial √3 x² - 11 x + 6√3  are 3√3 and 2 / √3.