Question

Find the zeroes of the polynomial 3x^2 - 4x +2

Answer 1

Answer:

=4√3x^2-2√3x-2√3=0

taking √3 common

4x^2-2x-2=0

4x^2+2x-4x-2=0

2x(2x+1)-2(2x+1)=0

(2x-2)(2x+1)=0

x=-1/2

and x=1

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Answer 2

Answer:

the zeroes of the polynomial are $x=\frac{3\pm8i}{6}$

Step-by-step explanation:

according to the question, we have to find the zeroes of a polynomial

$3x^2-4x+2$

this is a quadratic polynomial

a quadratic polynomial is a polynomial which has highest degree 2.

it can has either real or imaginary zeroes.

Zeroes are those values of x for which the value polynomial is zero.

we will use the quadratic formula

$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{3\pm\sqrt{16-24} }{6}$

$x= \frac{3 \pm\sqrt{-8}}{6}\\ x=\frac{3\pm8i}{6}$

the values of x come out to be imaginary that is it include i (iota)

this is because the term inside the square root is negetive.

when the square root comes out to be positive then the zeroes are real

the zeroes are $x=\frac{3\pm8i}{6}$

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