Find the zeroes of the polynomial 3x^2 + x – 2.
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Answered by
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Answer:
3x²+x-2
3x²+3x-2x-2
3x(x+1)-2(x+1)
(x+1)(3x-2)
x=-1 or x=2/3
Answered by
0
Answer:
x=-1 and x=2/3
Step-by-step explanation:
3x²+x-2=0
3x²+3x-2x-2=0
3x(x+1)-2(x+1)=0
(x+1)(3x-2)=0
x=-1,x=2/3
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