Question

Find the zeroes of the polynomial

3x^2-x-4​

Answer 1

Answer:

$3 {x}^{2} - x - 4 = 0 \\ \\ 3 {x}^{2} + 3x - 4x - 4 = 0 \\ \\ 3x(x + 1) - 4(x + 1) = 0 \\ \\ (x + 1) \: (3x - 4) = 0 \\ \\ x = - 1 \: \: or \: \: x = \frac{4}{3}$

Answer 2

Answer:

x=1,x=4/3

Step-by-step explanation:

1. 3x²-(4-3)x-4
2. 3x²-4x+3x-4
3. x(3x-4)+1

(3x-4)