Question

Find the zeroes of the polynomial 3x^3-10x^2+9x-2

Answer 1

Answer:

Step-by-step explanation:    α+β+∝= -b/a = -(-10/3) = 10/3

αβ+β∝+∝α= c/a= 9/3= 3

αβ∝= -d/a= 2/3

I think this may be  correct

Answer 2

Hey Friend ✌
here is u r Ans ⬇️⬇️⬇️


$x = 2 \\ \\ - \frac{1}{3} \\ \\ - 5$

$x - 2 = 0 \\ \\ 3x + 1 = 0 \\ \\ x + 5 = 0$

❤Hope This Helps u☺