Question

Find the zeroes of the polynomial : 3x square - 4 - 4x​

Answer 1

Answer:

Splitting the middle term, we get, 3x2 + 6x – 2x – 4 Taking the common factors out, we get, 3x(x+2) -2(x+2) On grouping, we get, (x+2)(3x-2) So, the zeroes are, x+2=0 ⇒ x= -2 3x-2=0⇒ 3x=2⇒x=2/3 Therefore,

zeroes are (2/3) and -2

Verification:

Sum of the zeroes = – (coefficient of x) ÷ coefficient of x2 α + β = – b/a – 2 + (2/3) = – (4)/3 = – 4/3 = – 4/3 Product of the zeroes = constant term ÷ coefficient of x2 α β = c/a Product of the zeroes = (- 2) (2/3) = –

Product of the zeroes = (- 2) (2/3) = – 4/3

Answer 2

Step-by-step explanation:

3x²-4x-4

3x²-6x+2x-4

3x(x-2)+2(x-2)

(3x+2)(x-2)

3x+2=0

x= -2/3

x-2=0

x=2

Therefore,

-2/3 and 2 are the zeroes of p(x)