Question

find the zeroes of the polynomial 3x2-27

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Answer 1

$3x {}^{2} - 27 = 0$

$3x {}^{2} = 27$

$x {}^{2} = 9$

$x = \sqrt{9}$

$x = + 3 \: \: or \: \: - 3$

Answer 2

3(x²-9) =0

x²-9=0

x²=9

x=+-3