Question

find the zeroes of the polynomial 3x² - 27 and verify the relationship between the zeroes and the coefficients.

Answer 1

Given that,

A polynomial, $3x^2-27$

To find,

Zeros.

Solution,

Let the given polynomial is f(x) such that,

$f(x)=3x^2-27$

To find the zeroes of the given polynomial,

Put f(x) = 0

$3x^2=27\\\\x^2=9\\\\x=\pm 3$

Zeroes are +3 and -3.

Sum of zeroes, $=\dfrac{-b}{a}$

In the given equation, a = 3, b = 0 and c = -27

Sum of zeroes, $=\dfrac{-b}{a}=-3+3=0$

The product of zeroes,

$=\dfrac{c}{a}\\\\-3\times 3=\dfrac{-27}{3}\\\\-9=-9$

Hence, this is the required solution.

Answer 2

minus nine is the answer ....