Question

find the zeroes of the polynomial 3x²+4root2x +3​

Answer 1

Answer:

3x²+ 4√2 x + 3 = 0

a = 3 , b = 4√2 , c = 3

x = -b± √b²- 4ac / 2a

x = -4√2 ± √(4√2)²- 4(3)3 / 2(3)

x = -4√2 ± √16 (2) - 36 / 6

x = -4√2 ± √32 - 36 / 6

x = -4√2 ± √-4 / 6

x = -4√2 ± (-2) / 6

x = -4√2 + (-2) / 6

x = -4√2 - 2 / 6

and

x = -4√2 - (-2) /6

x = -4√2 + 2 / 6

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