Question

Find the zeroes of the polynomial 3x2+x-2

Answer 1

3x2+x-2 = 3x^2+3x-2x-2 = 3x(x+1)-2(x+1) = (3x-2)(x+1) X= 2/3,-1

Answer 2

Hi Mate Here is the required answer;:-

3x^2 + x-2

To find the zeroes of the polynomial,

3x^2+x-2 =0

By splitting the middle term,

3x^2+ 3x-2x -2= 0

3x(x+1) -2(x+1)= 0

(3x-2) (x+1) =0

So, x= 2/3,. x= -1.

Hope this helps you...