find the zeroes of the polynomial 3xcube_10xsqure+9x_2
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3x³ - 10x² + 9x - 2
= 3x³ - 3x² - 7x² + 7x + 2x - 2
= 3x²(x - 1) - 7x(x - 1) + 2(x - 1)
= (x - 1)(3x² - 7x + 2)
= (x - 1)(3x² - x - 6x + 2)
= (x - 1)[x(3x - 1) - 2(3x - 1)]
= (x - 1)(3x - 1)(x - 2).
So, zeroes of the polynomial are x = 1, x = 1/3, x = 2.
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