Math, asked by s15309alikhith10751, 1 month ago

Find the zeroes of the polynomial 4√3x2 +5x -2√3.​

Answers

Answered by WildFoxx
4

Answer:

The given polynomial f(x)

= 4√3 x^2 +5x - 2√3

= 4√3 x^2 + 8x - 3x - 2√3

= 4x(√3 x +2) - √3 (√3 x +2)

= (√3x+2)(4x-√3)

Hence the zeroes are -2/√3 and √3/4

Sum of the roots = -2/√3 + √3/4 = -2√3/3 + √3/4 = (-8√3+3√3)/12 = -5√3/12

Sum of the roots = -b/a = -5/4√3 = -5√3/12

Hence sum of the roots =-b/a.

Product of the roots = (-2/√3)(√3/4) = -1/2.

Product of the roots = c/a = -2√3/4√3 = -1/2.

So product of the roots = c/a.

Thus, the relationship between the roots and coefficients is verified.

Answered by Himalaysaikia
1

Answer:

Please refer to the above attachment to get your answer

Step-by-step explanation:

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