Question

Find the zeroes of the polynomial 4 —x2
(a) 2 (b) 2√2 (c) 0 (d) 4

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=\pm2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies 4- {x}^{2} = 0 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: x = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies 4 - {x}^{2} = 0 \\ \\ \tt: \implies {x}^{2} = 4 \\ \\ \tt: \implies x = \sqrt{4} \\ \\ \green{\tt: \implies x = \pm2}$

$\tt \circ \: a = 1 \\ \\ \tt \circ \: b = 0 \\ \\ \tt \circ \: c = -4$

$\bold{Alternate\:method} \\ \tt: \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt: \implies x = \frac{ - 0\pm \sqrt{ {0}^{2} - 4 \times 1 \times (-4) } }{2 \times 1}$

$\tt : \implies x = \frac{ \pm \sqrt{0+16} }{2} \\ \\ \tt : \implies x = \frac{ \pm 4 }{2} \\ \\ \green{\tt : \implies x = \pm 2 }$