Question

Find the zeroes of the polynomial 4u^2 + 8u

Answer 1

Hello Friend.

Here is ur answer below,,

$4u {}^{2} + 8u = 0 \\ = > 4u {}^{2} + 8u = 0 \\ = > 4u(u + 2) = 0 \\ = > 4u = 0 \\ = > u = \frac{0}{4} \\ = > u = 0 \\ or \\ = > u + 2 = 0 \\ = > u = - 2 \\ \\ so \: that \: zeros \: are \: (0 \: and \: - 2)$

I hope that helps you