Question

Find the zeroes of the polynomial 4u^+8u and verify the relationship between the zeroes and the coefficients​

Answer 1

Step-by-step explanation:

taking common we get

4u (u+2)

4u=0 u+2=0

u=0 u=-2

here a=4 b=8 c=0

sum of zeroes=-b/a

0+(-2) =-8/4

-4 =-4

LHS=RHS

Product of zeroes =c/a

0×-2 = 0/4

0= 0

LHS=RHS

hence relationship is verified