find the zeroes of the polynomial 4x^2-4x-8
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Answer:
-1 and 2 are the zeros of the given polynomial
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Answer:Ans:x=2,-1
Step-by-step explanation:
4x^2-4x-8=0
4x^2-8x+4x-8=0
4x(x-2)+4(x-2)=0
(x-2) (4x+4)=0
x=2,-4/4
x=2,-1
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