Question

Find the zeroes of the polynomial 4x^2-7

Answer 1

Zeroes of 4x2 - 7.

=> 4x2 - 7 = 0

=> 4x2 = 7

=> x2 = 7/4

=> x = ± √7/4

Therefore, zeroes of the polynomial are √7/4 and - √7/4.

Answer 2

Concept

A polynomial's zeros are defined as the points at which the polynomial as a whole becomes zero. The term zero polynomial refers to a polynomial with a value of zero . The highest power of the variable $x$ is the polynomial's degree. A linear polynomial is a polynomial of degree $1.$

Given

A polynomial $4x^{2} -7$

Find

Zeroes of the polynomial

Solution

$4x^{2} -7\\4x^{2} =7\\x^{2} =\frac{7}{4} \\x=\pm \sqrt{\frac{7}{4} } \\x=\pm \frac{\sqrt{7}}{2}$

Hence the zeroes of the polynomial are

$\pm \frac{\sqrt{7} }{2}$