find the zeroes of the polynomial 4x²-4x-8
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Answer:
Step-by-step explanation:
4x² - 4x - 8 = 0
→ 4(x² - x - 2) = 0
→ x² - x - 2 = 0
→ x² - 2x + x - 2 = 0
→ x(x - 2) + 1(x - 2) = 0
→ (x - 2)(x + 1) = 0
→ x = 2 & (-1) negative no be neglated therefore x=2
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